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Honglin Zhang · Answer 1 · 2023-12-06T07:47:49+0000

Given:

The radius of the orbit is,

$\begin{gathered} r=5.00*10^2\operatorname{km} \\ =5.00*10^5m \end{gathered}$

The radius of the Earth is,

The mass of the Earth is,

$M=5.97*10^(24)\operatorname{kg}$

The gravitational constant is,

$G=6.67*10^(-11)N.m^{2^{}}.kg^(-2)$

The time period of the satellite is,

$\begin{gathered} T=2\pi\sqrt[]{((R+h)^3)/(GM)} \\ =2\pi\sqrt[]{((5.00*10^5+6.38*10^6)^3)/(6.67*10^(-11)*5.97*10^(24))} \\ =5682\text{ s} \\ =1.58\text{ h} \end{gathered}$

Hence the option c is correct.

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