Question

What is the extension force (in lbf) of a 5 inch diameter cylinder with a pressure of 200psi?

Answer 1

The area of the cylinder can be given as,

`A=\pi((d)/(2))^2`

Substitute the known value,

`\begin{gathered} A=(3.14)(\frac{5\text{ in}}{2})^2 \\ =19.625in^2 \end{gathered}`

The extension force acting on the cylinder is,

`F=PA`

Substitute the known values,

`\begin{gathered} F=(200psi)(19.625in^2)(\frac{1\text{ lbf}}{1psiin^2})_{} \\ =3925\text{ lbf} \end{gathered}`

Thus, the force exerted on the cylinder is 3925 lbf.