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Complete the third row of the table.Express the temperature in degrees Celsius to three significant figures.

Complete the third row of the table.Express the temperature in degrees Celsius to-example-1

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Answer:


T_2\text{ = 17.3}\degree C

Step-by-step explanation:

Here, we want to get the initial temperature

From Charles' law, we know that at constant pressure, the volume of a given mass of gas is directly proportional to its temperature

Mathematically, we can have this written as:


\frac{V_1}{T_1\text{ }}=(V_2)/(T_2)

We can rewrite the formula in terms of the missing value as follows:


T_2\text{ = }(V_2T_1)/(V_1)

Let us write out the values given, not forgetting that we have to convert the temperature value to Kelvin by adding 273.15 K

Thus, we have:


\begin{gathered} V_1\text{ = 2.21 L} \\ T_1\text{ = 14.7 + 273.15 = 287.85 K} \\ V_2\text{ = 2.23 L} \\ T_2\text{ = ?} \end{gathered}

Substituting these values in the re-written formula, we have it as:


T_2=\text{ }(2.23*287.85)/(2.21)\text{ = 290.455 K}

Finally, what we have to do is to convert this temperature to degrees celsius by subtracting 273.15 K

We have this as:


290.455\text{ - 273.15 = 17.3 }

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