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The number of bank failures decayed approximately exponentially from 157 bank failures in 2010 to 18 bank failures in 2014. Estimate the number of bank failures in2018.

User Schmop
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This problem deals with an exponential decay process. The general equation describing a decay is written as


y=y_0e^(-kt)

where y0 represents the initial state of the system and k is the decay constant.

In the given problem, we have y0 = 157. After t =4, the value of y becomes 18. We will be using these values to solve first the decay constant of the problem. We have


\begin{gathered} (y)/(y_0)=e^(-kt) \\ -kt=\ln ((y)/(y_0)) \\ -kt=\ln ((18)/(157)) \\ -kt=-2.16587 \\ k=(-2.16587)/(-4)=0.5415 \end{gathered}

We use this decay constant to solve the number of bank failures in 2018. In the year 2018, t = 8. Hence, the number of bank failures at this time will be


\begin{gathered} y=(157)e^(-(0.5415*8)) \\ y=2.063 \\ y\approx2 \end{gathered}

There will be 2 bank failures in 2018.

User Oli Studholme
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