This problem deals with an exponential decay process. The general equation describing a decay is written as
![y=y_0e^(-kt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/speulhiptc1an7f8rxktq4ss5xh4mu7yd9.png)
where y0 represents the initial state of the system and k is the decay constant.
In the given problem, we have y0 = 157. After t =4, the value of y becomes 18. We will be using these values to solve first the decay constant of the problem. We have
![\begin{gathered} (y)/(y_0)=e^(-kt) \\ -kt=\ln ((y)/(y_0)) \\ -kt=\ln ((18)/(157)) \\ -kt=-2.16587 \\ k=(-2.16587)/(-4)=0.5415 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/s17p4r4arl2cixxu9wijdsdciaazbua4gv.png)
We use this decay constant to solve the number of bank failures in 2018. In the year 2018, t = 8. Hence, the number of bank failures at this time will be
![\begin{gathered} y=(157)e^(-(0.5415*8)) \\ y=2.063 \\ y\approx2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wqj32pa4jcqzqhte7z3wdwvs8wn2q84s8j.png)
There will be 2 bank failures in 2018.