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Which equation represents a line which is perpendicular to the line 7x+3y=-18

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In order to determine the equation with a line perpendicular to the given equation, consider that for two perpendicular lines, the relation in between their slopes is:

m1 = -1/(m2)

where m1 and m2 are the slopes of the lines.

Write the given equation in slope-intercept form to identify the slope m1, as follow:

7x + 3y = -18 subtract 7x both sides

3y = - 7x - 18 divide by 3 both sides

y = -7/3 x - 6

remind that the general form of the equation of a line can be written as follow:

y = mx + b

where m is the slope. Based on the expression for y = -7/3 x - 6, you have

m1 = -7/3

then, calculate m2:

m2 = -1/(m1)

m2 = -1/(-7/3)

m2 = 3/7

Hence, it is necessary that the perpendicular line has a positive slope of 3/7.

Fromt the given answer choices, you can notice that the only option with the required slope is:

y = 3/7 x + 5

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