The area of the trapezium is calculated as follows:
![A=(b_1+b_2)/(2)\cdot h](https://img.qammunity.org/2023/formulas/mathematics/college/m1xti1xe7y6q9mqdjs5yh9xvz6decwsimt.png)
Where b1 and b2 are the lengths of the bases (the parallel sides) and h is the height (perpendicular to the bases).
The figure gives us: b1 = 16 yd, b2 = 20 yd, h = 10 yd. Substituting:
![A=\frac{16\text{ yd}+20\text{ yd}}{2}\cdot10\text{ yd}](https://img.qammunity.org/2023/formulas/mathematics/college/c541or8h1ac18ddk9jj14y53mt8n6kijvt.png)
Calculating:
![\begin{gathered} A=18\text{ yd}\cdot10\text{ yd} \\ \\ \boxed{A=180\text{ }yd^2} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/b3fmtvozndyj9gdg0xpahj3sshdqnzcc6z.png)
Answer: C) 180 yd^2