Question

A car battery with a potential difference of 11.4 volts is connected to a starter motor with a resistance of 0.242 ohms. If the startup time is 1.54 seconds, how many electrons flow out of the battery during this time? Answer must be in 3 significant digits.

Answer 1

Given

The potential difference is V=11.4 V

Resistance is R=0.242 ohm

Time taken, t=1.54 sec

To find

The number of electron flow.

Step-by-step explanation

Let the number of electron be n

We know current is charge per unit time

Thus,

`I=(q)/(t)=(ne)/(t)`

By Ohm's law,

`\begin{gathered} V=RI \\ \Rightarrow V=(Rne)/(t) \\ \Rightarrow11.4=(0.242* n*1.6*10^(-19))/(1.54) \\ \Rightarrow n=4.53*10^(20) \end{gathered}`

Conclusion

The number of electron flow is

`4.53*10^(20)`