Given:
A town’s population increases at a constant rate.
In 2010: population = 54,000
In 2012: population = 79,000
The will use the function of the exponential growth:

where: P₀ is the initial population
r is the rate of increase
t is the number of years from 2010
So, we'll substitute with the given values to find the rate of increase

Solve the last equation to find (r) as follows:
![\begin{gathered} (79000)/(54000)=(1+r)^2 \\ \\ (1+r)^2=(79)/(54) \\ \\ 1+r=\sqrt[]{(79)/(54)} \\ \\ r=\sqrt[]{(79)/(54)}-1\approx0.2095 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/k3b83c96shvtkgearzja60k5rjmk1zbcgb.png)
We will use the value of (r) to find the population in 2016
So, t = 2016 - 2010 = 6

So, the answer will be:
The population will be 169,081 in 2016.