The surface of a square pyramid is the sum of the area of its four triangular faces and its base.
Since the side length of its base is 2 m, its base area is 2² = 4 m²
Since each of its triangular face has a base 2 m and a height 2 m, its area is (2*2)/2 = 2 m²
Therefore, the surface area of the pyramid is 4 + 4*2 = 12 m²