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If JN =14x -17 and NL = 3x +38, solve for X

If JN =14x -17 and NL = 3x +38, solve for X-example-1
User Dustan
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2 Answers

3 votes

Answer:

Explanation:

First you would set up your equation which is....

14x - 17 = 3x + 38

-3x -3x

Then subtract 3x from both sides of the equation to get...

11x - 17 = 38

+17 +17

Then add 17 to both sides to then get

11x = 55 Finally divide by 11 on both sides to get...

x = 5 as the final answer

User Jeremy Lakeman
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3.0k points
2 votes

From the picture, N is the midpoint of JL, this means that JN is congruent to NL. Then,

14x - 17 = 3x + 38

14x - 3x = 38 + 17

11x = 55

x = 55/11

x = 5

User Diegocstn
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3.1k points