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Given B(17, 5), C(11, -3), D(-1, 2), and E(x, -6), find the value of x so that BC is parallel to DE

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First we need to find the equation of the line BC

B (17,5)=(x1,y1)

C(11,-3)=(x2,y2)

First we need to find the slope


m=(y_2-y_1)/(x_2-x_1)
m=(-3-5)/(11-17)=(-8)/(-6)=(4)/(3)

Because DE is parallel to BC they have the same slope

D(-1,2)=(x1,y1)

E(x,-6)=(x2,y2)


m=(4)/(3)=(-6-2)/(x+1)=(-8)/(x+1)


(4)/(3)=(-8)/(x+1)
((x+1)4)/(3)=-8
(4x+4)/(3)=-8
4x+4=-8(3)
4x+4=-24
4x=-24-4
4x=-28
x=(-28)/(4)=-7

x=-7

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