Question

Write the equation that describes that function.Express it in slope-Intercept form.

Answer 1

`y=(1)/(4)x-3`

Explanations:

The equation of a line in slope-intercept form is expressed as:

`y=mx+b`

where:

• m is the ,slope

,

• b is the ,y-intercept

From the graph, the y-intercept is the point where the line crosses the y-axis. The y-intercept is (0, -3)

Determine the slope using the coordinate point (0, -3) and (4, -2) on the line

`\begin{gathered} m=(y_2-y_1)/(x_2-x_1) \\ m=(-2-(-3))/(4-0) \\ m=(-2+3)/(4) \\ m=(1)/(4) \end{gathered}`

Substitute the slope and y-intercept into the equation to have:

`\begin{gathered} y=mx+b \\ y=(1)/(4)x+(-3) \\ y=(1)/(4)x-3 \end{gathered}`

Hence the equation of the line in slope-intercept form is y = 1/4 x - 3