Question

Solve each equation by using the square root property. 2x^2–3=7.

Answer 1

`x=\pm\sqrt[]{5}`

Step-by-step explanation

`2x^2-3=7`

Step 1

add 3 in both sides

`\begin{gathered} 2x^2-3=7 \\ 2x^2-3+3=7+3 \\ 2x^2=10 \\ \end{gathered}`

Step 2

divide both sides by 2

`\begin{gathered} 2x^2=10 \\ (2x^2)/(2)=(10)/(2) \\ x^2=5 \\ \end{gathered}`

Step 3

then take the square root of both sides and solve for the variable

`\begin{gathered} x^2=5 \\ \sqrt[]{x^2}=\text{ }\pm\sqrt[]{5} \\ x=\pm\sqrt[]{5} \end{gathered}`