Question

How do I solve and what would be the answer

Answer 1

Given

The area of the rectangle is represented as,

`A=14x^3-35x^2+42x`

And, the length is represented as,

`l=7x`

To find the breadth of the rectangle.

Now,

The area of the rectangle is given by,

`A=l* b`

Then,

`b=(A)/(l)`

Substitute the values of A and l in the above equation.

Then,

`b=(14x^3-35x^2+42x)/(7x)`

Since the common terrm in 14x^3-35x^2+42x is 7x.

Then,

`\begin{gathered} b=(7x(2x^2-5x+6))/(7x) \\ b=2x^2-5x+6 \end{gathered}`

Hence, the breadth of the rectangle is 2x^2-5x+6.