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How do I solve and what would be the answer

How do I solve and what would be the answer-example-1

1 Answer

4 votes

Given

The area of the rectangle is represented as,


A=14x^3-35x^2+42x

And, the length is represented as,


l=7x

To find the breadth of the rectangle.

Now,

The area of the rectangle is given by,


A=l* b

Then,


b=(A)/(l)

Substitute the values of A and l in the above equation.

Then,


b=(14x^3-35x^2+42x)/(7x)

Since the common terrm in 14x^3-35x^2+42x is 7x.

Then,


\begin{gathered} b=(7x(2x^2-5x+6))/(7x) \\ b=2x^2-5x+6 \end{gathered}

Hence, the breadth of the rectangle is 2x^2-5x+6.

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