The equatio of a circle with radius 3 would be: x^2 + y^2=9. If the radius is 9, then the equation would be:
x^2+ y^2 = 81. If a point is inside the circle then x^2+ y^2 <= 81
A. (-9)^2+ (3)^2 <= 81 (Replacing point A)
A. 81 +9 <= 81 (Raising both numbers to the power of 2)
A. 90 <=81 (As 90 is greater than 81, this point is not inside the circle)
The answer is the option A.