Question

a stone is dropped from the top of a cliff. it is observed to hit the ground 5.78 s later how high is the cliff?

Answer 1

Using the formula;

H= ut + 1/2 gt²

The initial velocity = 0

Hence H= 1/2 gt²

g= 10m/s t= 5.78 s

H = 1/2 x 10 x 5.78²

H = 167.042 m

H = 167 m approximately