Part A:
In 2000, the population was 6.26 million.
In 2015, the population was 7 million.
The general form of the exponential function is given by
![A=A_0e^(k\cdot t)](https://img.qammunity.org/2023/formulas/mathematics/college/hcp6ez73ypxvpb6ak5sgpt50rxbhrfm3ls.png)
Where A0 is the initial population (6.26 million), k is the growth rate, and t is the number of years after 2000.
Let us first find the growth rate.
We are given that In 2015, the population was 7 million.
![\begin{gathered} A=A_0e^(k\cdot t) \\ 7=6.26e^(k\cdot15) \\ (7)/(6.26)=e^(k\cdot15) \\ \ln ((7)/(6.26))=\ln (e^(k\cdot15)) \\ 0.1117=k\cdot15 \\ k=(0.1117)/(15) \\ k=0.0074 \\ k=0.01 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/m9kdy49ech1aqr5lvxmmybniunidvcmgm9.png)
So, the growth rate is 0.01 (rounded to 2 decimal places)
Therefore, the exponential growth model is
![A=6.26e^(0.01t)](https://img.qammunity.org/2023/formulas/mathematics/college/1743rouptnfggqxdh5f9i2yfxh4ius6a4o.png)
Part B:
We need to find the year for which the population will be 12 million.
Let us substitute A = 12 into the exponential growth function and solve for t
![\begin{gathered} A=6.26e^(0.01t) \\ 12=6.26e^(0.01t) \\ (12)/(6.26)=e^(0.01t) \\ \ln ((12)/(6.26))=\ln (e^(0.01t)) \\ 0.6507=0.01t \\ (0.6507)/(0.01)=t \\ 65=t \\ t=65\: \text{years} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nha5wwa5erorfr0tgllmuolhzqk93ls3xi.png)
Therefore, the country's population will be 12 million in the year 2065