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Do you no the answer to this f(x)=4x^2-17x+3Solve for the values of x

User Cmt
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1 Answer

5 votes

Answer:


x=\frac{17+\sqrt[]{241}}{8},\frac{17-\sqrt[]{241}}{8}

Step-by-step explanation:

Given the below function;


f(x)=4x^2-17x+3

Note that a quadratic equation in standard form is generally given as;


y=ax^2+bx+c

If we compare both of the equations above, we can deduce that;


a=4,b=-17,c=3

We'll now use the below quadratic formula to solve for the values of x as seen below;


\begin{gathered} x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{17\pm\sqrt[]{(-17)^2-4\cdot4\cdot3}}{2\cdot4} \\ x=\frac{17\pm\sqrt[]{289-48}}{8} \\ x=\frac{17\pm\sqrt[]{241}}{8} \\ \therefore x=\frac{17+\sqrt[]{241}}{8},\frac{17-\sqrt[]{241}}{8} \end{gathered}

User Rithwik
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