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The General Social Survey included a question about how many hours the respondent spent doing volunteer activities outside of their own home. For the 515 respondents, the sample mean was 6.15 hours and the sample standard deviation was 16.53 hours. Find the margin of error for a 95% confidence interval for the population mean amount of time spent doing volunteer activities outside of their own home.1.431 1.428 1.2 2.320

User Yangsuli
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1 Answer

2 votes

ANSWER:

2nd option: 1.428

Explanation:

Given:

Sample size (n) = 515

Standard deviation (σ) = 16.53

Confidence level: 95%

The margin of error can be calculated as follows:


\begin{gathered} E=z_c\cdot(σ)/(√(n)) \\ \\ \text{ For the 95\% confidence level the value of Zc is equal to 1.96, therefore, we substitute each value:} \\ \\ E=1.96\cdot(16.53)/(√(515)) \\ \\ E=1.42766\cong1.428 \end{gathered}

Therefore, the correct answer is 2nd option: 1.428

User Trinculo
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