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Im not understanding area base and hight.

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As the statement indicates, the formula to find the area of ​​a trapezoid is


\begin{gathered} A=(1)/(2)h(b_1+b_2) \\ \text{Where A is the area} \\ h\text{ is the height,} \\ b_1\text{ is a short base and} \\ b_2\text{ is a long base of the trapezoid} \end{gathered}

Graphically

So, you have


\begin{gathered} b_1=9\operatorname{cm} \\ b_2=15\operatorname{cm} \\ h=14\operatorname{cm} \end{gathered}
\begin{gathered} A=(1)/(2)h(b_1+b_2) \\ A=(1)/(2)(14\operatorname{cm})(9\operatorname{cm}+15\operatorname{cm}) \\ A=(1)/(2)(14\operatorname{cm})(24\operatorname{cm}) \\ A=(7\operatorname{cm})(24\operatorname{cm}) \\ A=168\operatorname{cm}^2 \end{gathered}

Therefore, the area of the trapezoid is 168 square centimeters.

Im not understanding area base and hight.-example-1
User Tom Finney
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