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Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3
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Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x-example-1
User Anthony Leach
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1 Answer

4 votes


x=(100)/(14)

Step-by-step explanation

As BD is a perpendicular bisector


\begin{gathered} AD=DC\text{ and AC=2AD} \\ \text{replacing} \\ AC=2AD \\ 10x-20=2(40-2x) \\ 10x-20=80-4x \\ 10x+4x=80+20 \\ 14x=100 \\ x=(100)/(14) \end{gathered}


\begin{gathered} \\ \end{gathered}

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x-example-1
User Alex Busuioc
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