Register

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3
196k views
3 votes
Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x + 5BAD=4x+3

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x-example-1
User Anthony Leach
by
8.4k points

1 Answer

4 votes


x=(100)/(14)

Step-by-step explanation

As BD is a perpendicular bisector


\begin{gathered} AD=DC\text{ and AC=2AD} \\ \text{replacing} \\ AC=2AD \\ 10x-20=2(40-2x) \\ 10x-20=80-4x \\ 10x+4x=80+20 \\ 14x=100 \\ x=(100)/(14) \end{gathered}


\begin{gathered} \\ \end{gathered}

Given : BD is a perpendicular bisectsr AD = 40 - 2 BC = 8x + 10 AC = 10x - 20 BD = 12x-example-1
User Alex Busuioc
by
8.7k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!