Question

The length of the remaining piece of a beam is

Answer 1

`4y^(2)+5y+9`

1) Since the total length of that beam is expressed by this polynomial:

`5y^2+5y+1`

and a fraction of it is expressed by:

`y^2-8`

2) We can find the remaining length by subtracting from 5y²+5y+1 the fraction y²-8

`\begin{gathered} 5y^2+5y+1-(y^2-8) \\ \\ 5y^2+5y+1-y^2+8 \\ \\ 4y^2+5y+9 \end{gathered}`

Thus, the answer is 4y²+5y+9