Question

Can you help me with this assignment?

Answer 1

To find the perimeter, we have to find AB which is the hypothenuse of the right triangle ADB. Let's use Pythagorean's Theorem.

`AB^2=BD^2+AD^2`

Replacing the given values, we have.

`\begin{gathered} AB^2=4^2+3^2 \\ AB=\sqrt[]{16+9}=\sqrt[]{25} \\ AB=5 \end{gathered}`

Given that AB = BC, then BC = 5.

Moreover, remember that the perimeter is the sum of all sides.

`P=5+5+3+3=16`

Hence, the perimeter is 16 units long.