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4 votes
Can you help me with this assignment?

User Lelon
by
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1 Answer

4 votes

To find the perimeter, we have to find AB which is the hypothenuse of the right triangle ADB. Let's use Pythagorean's Theorem.


AB^2=BD^2+AD^2

Replacing the given values, we have.


\begin{gathered} AB^2=4^2+3^2 \\ AB=\sqrt[]{16+9}=\sqrt[]{25} \\ AB=5 \end{gathered}

Given that AB = BC, then BC = 5.

Moreover, remember that the perimeter is the sum of all sides.


P=5+5+3+3=16

Hence, the perimeter is 16 units long.

User Cheerless Bog
by
6.5k points
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