Question

Graph the image of AABC after a translation 6 units right and 7 units down.

Answer 1

Step-by-step explanation:

From the given graph, we can see that the vertices of triangle ABC are;

`\begin{gathered} A(4,2) \\ B(4,4) \\ C(-4,1) \end{gathered}`

To translate 6 units right, we have to add 6 to the x-coordinates of each of the vertices of the triangle and to translate 7 units down, we have to subtract 7 from the y-coordinates of each of the vertices of the triangle as seen below;

`A^(\prime)(4+6,2-7)\rightarrow A^(\prime)(10,-5)`
`B^(\prime)(4+6,4-7)\rightarrow B^(\prime)(10,-3)`
`C^(\prime)(-4+6,1-7)\rightarrow C^(\prime)(2,-6)`

Below is the graph of the image of triangle ABC which is triangle A'B'C';