Question

Assume that theings at freezing on a batch of thermometers are normally distributed with a mean of 0°Cand a standard deviation of 1.00C. A single thermometer is randomly selected and tested. Find P88, the 88-percentile. This is the temperature reading separating the bottom 88% from the top 12%.P 38 =*C(Round answer to three decimal places)

Answer 1

To solve this question you need to check a z-table.

88% corresponds to a z score of 1.175

Substituting z on the z score formula, then x can be solved as 1.175°C