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At the end of the school year, a high school chemistry teacher asks one of the students to stay after school and help clean the storage room. While cleaning, the student finds a rectangular block of metal that is not labeled and is therefore unknown.a) The student wants to identify the metal using density. The student measures each side of the block (using a centimeter ruler) and determines the length is 3.00 cm, height is 5.00 cm, and width is 5.00 cm. The student then takes the mass of the block using an electronic balance and reports the mass as 337.50 g. What is the density of the rectangular block? Make sure to show all work, use significant figures, and end with a unit.b) The student then researches the density of different materials, as seen in the table below. What is the identity of the rectangular block?c) The student believes they have determined the identity of the substance. However, in order to be certain they must collect more data. List at least two physical properties and one chemical property that could be tested in the table below. Also, list how you would collect data about each property in the lab.

At the end of the school year, a high school chemistry teacher asks one of the students-example-1
At the end of the school year, a high school chemistry teacher asks one of the students-example-1
At the end of the school year, a high school chemistry teacher asks one of the students-example-2

1 Answer

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ANSWER

The density of the block is 4.5 g/cm^3

The block is identified as titanium

Physical properties

1. Titanium has a low density

2. Titanium has a very high strength

Chemical properties

1. It is radioactive in nature

Step-by-step explanation

Given that;

The length of the block is 3.00 cm

The height of the block is 5.00 cm

The width of the block is 5.00 cm

The mass of the block is 337.50g

Follow the steps below to find the density of the block

Step 1; Find the volume of the block


\text{ Recall, that volume = l x w }*\text{ h}
\begin{gathered} \text{ Volume = 3 }*\text{ 5}*\text{ 5} \\ \text{ Volume = 3 }*\text{ 25} \\ \text{ Volume = 75 cm}^3 \end{gathered}

The volume of the block is 75 cubic meters

Step 2; Find the density of the block using the formula below


\text{ Density = }\frac{\text{ mass}}{\text{ volume}}
\begin{gathered} \text{ Density = }\frac{\text{ 337.50}}{\text{ 75}} \\ \text{ Density = 4.5 g/cm}^3 \end{gathered}

The density of the block is 4.5 g/cm^3

Hence, the block is identified as titanium

The next step is to write the physical and chemical properties of titanium

Physical properties

1. Titanium has a low density

2. Titanium has a very high strength

Chemical properties

1. It is radioactive in nature

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