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all you need is in the photo please put only the answer Don't do step by step please answer fast. pleaseeeeeeeeeeplessrs

all you need is in the photo please put only the answer Don't do step by step please-example-1
User Bharath Mg
by
7.1k points

1 Answer

7 votes

Quadratic formula is represented by:


x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}

Information given:

a=2

b=2

c=-12

Then, we have to substitute each term in the quadratic formula:


x=\frac{-2\pm\sqrt[]{2^2-4(2)(-12)}}{2(2)}

Solve for x1:


\begin{gathered} x_1=\frac{-2+\sqrt[]{4+96}}{4}=\frac{-2+\sqrt[]{100}}{4} \\ x_1=(-2+10)/(4)=(8)/(4)=2 \end{gathered}

For x2:


\begin{gathered} x_1=\frac{-2-\sqrt[]{4+96}}{4}=\frac{-2-\sqrt[]{100}}{4} \\ x_2=(-2-10)/(4)=-(12)/(4)=3 \end{gathered}

So, x1=2 and x2=3

User Jamill
by
6.8k points
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