Question

all you need is in the photo please put only the answer Don't do step by step please answer fast. pleaseeeeeeeeeeplessrs

Answer 1

Quadratic formula is represented by:

`x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}`

Information given:

a=2

b=2

c=-12

Then, we have to substitute each term in the quadratic formula:

`x=\frac{-2\pm\sqrt[]{2^2-4(2)(-12)}}{2(2)}`

Solve for x1:

`\begin{gathered} x_1=\frac{-2+\sqrt[]{4+96}}{4}=\frac{-2+\sqrt[]{100}}{4} \\ x_1=(-2+10)/(4)=(8)/(4)=2 \end{gathered}`

For x2:

`\begin{gathered} x_1=\frac{-2-\sqrt[]{4+96}}{4}=\frac{-2-\sqrt[]{100}}{4} \\ x_2=(-2-10)/(4)=-(12)/(4)=3 \end{gathered}`

So, x1=2 and x2=3