Question

Write the equation of the line Passes through (6,-6) and (8,-3) Write the answer in slope intercept form

Answer 1

GIven:

The given points are (6,-6) and (8,-3).

The objective is to find the equation of the line in slope intercept form.

Consider the given points are,

`\begin{gathered} (x_1,y_1)=(6,-6) \\ (x_2,y_2)=(8,-3) \end{gathered}`

The general equation for straight line through two points is,

`\begin{gathered} y-y_1=m(x-x_1) \\ y-y_1=(y_2-y_1)/(x_2-x_1)(x-x_1) \end{gathered}`

Here, m represents the slope of the equation.

On plugging the values in the above equation,

`\begin{gathered} y-(-6)=(-3-(-6))/(8-6)(x-6) \\ y+6=(-3+6)/(2)(x-6) \\ y=(3)/(2)(x-6)-6 \\ y=(3x)/(2)-(3*6)/(2)-6 \\ y=(3x)/(2)-9-6 \\ y=(3x)/(2)-15 \end{gathered}`

Hence, the equation of line in slope intercept form is y = (3/2)x-15.