Given:
a.) Approximately normal with a mean of 460 and a standard deviation of 31.
b.) The probability that the score of a randomly selected examinee is more than 530.
Step 1: Let's determine the z-score.
![\text{ z-score = }(x-\mu)/(\sigma)](https://img.qammunity.org/2023/formulas/mathematics/college/xqhdj3dam531duhx2mhng9m21fivtu7h9b.png)
![\text{ = }\frac{530\text{ - 460}}{31}](https://img.qammunity.org/2023/formulas/mathematics/college/3zzt11qolgl1mzauaja1qt2ps7czqdxqn2.png)
![\text{ = 2.258064516129032}](https://img.qammunity.org/2023/formulas/mathematics/college/m5b3k7xdlb3tqqwm768radppv90uzjbcxo.png)
![\text{ z-score }\approx\text{ 2.26}](https://img.qammunity.org/2023/formulas/mathematics/college/30er55h8gise77sadkauv4lpqkvw88fhpj.png)
Step 2: Let's use the z-score table to determine its equivalent probability.
From the given chart, it appears that at z-score of 2.26, the probability is 0.9881
Therefore, the answer is 0.9881 or 98.81%