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The GMAT scores of all examinees who took that test this year produced a distribution that is approximately normal with a mean of 460 and a standard deviation of 31.The probability that the score of a randomly selected examinee is more than 530, rounded to three decimal places, is:Type your answer here

User Sudheej
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Given:

a.) Approximately normal with a mean of 460 and a standard deviation of 31.

b.) The probability that the score of a randomly selected examinee is more than 530.

Step 1: Let's determine the z-score.


\text{ z-score = }(x-\mu)/(\sigma)
\text{ = }\frac{530\text{ - 460}}{31}
\text{ = 2.258064516129032}
\text{ z-score }\approx\text{ 2.26}

Step 2: Let's use the z-score table to determine its equivalent probability.

From the given chart, it appears that at z-score of 2.26, the probability is 0.9881

Therefore, the answer is 0.9881 or 98.81%

The GMAT scores of all examinees who took that test this year produced a distribution-example-1
User Idealmind
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