Question

This is a bit hard and I’ve tried multiple times and still don’t get itA. F(6)B. F(-4)

Answer 1

To solve this question, follow the steps below.

Part A.

Step 01: Substitute x by 6.

`\begin{gathered} f(x)=3x^2+5x-5 \\ f(6)=3\cdot6^2+5\cdot6-5 \end{gathered}`

Step 02: Solve the square.

`f(6)=3\cdot36+5\cdot6-5`

Step 03: Solve the multiplication.

`\begin{gathered} f(6)=3\cdot36+5\cdot6-5 \\ f(6)=108+30-5 \end{gathered}`

Step 04: Solve addition and subtraction.

`\begin{gathered} f(6)=138-5 \\ f(6)=133 \end{gathered}`

Answer: f(6) = 133.

Part B.

To find f(-4), follow the same steps as above.

Step 05: Substitute x by -4.

`\begin{gathered} f(x)=3x^2+5x-5 \\ f(-4)=3\cdot(-4)^2+5\cdot(-4)-5 \end{gathered}`

Step 06: Solve the square.

`f(-4)=3\cdot16+5\cdot(-4)-5`

Step 07: Solve the multiplication.

`f(-4)=48-20-5`

Step 08: Solve addition and subtraction.

`\begin{gathered} f(-4)=28-5 \\ f(-4)=23 \end{gathered}`

Answer: f(-4) = 23.

In summary,

A) f(6) = 133.

B) f(-4) = 23.