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Through (-2,1) and (5,-3)

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The slope intercept form of the equation is express as;


y_{}=(y_2-y_1)/(x_2-x_1)(x-x_1)+y_1

The given points are (-2,1) and (5,-3);


\text{ Substitute x}_1=-2,y_1=1,x_2=5,y_2=-3

Thus, the expression will be;


y_{}=(y_2-y_1)/(x_2-x_1)(x-x_1)+y_1

User KotoMJ
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