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The equation of line u is y=3/8×+6. line v is perpendicular to u. what is the slope of v?

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The given equation is


y=(3)/(8)x+6

We know that line v is perpendicular to u (the given equation).

The definition for perpendicularity in this case is


m_u\cdot m_v=-1

Additionally, from the given equation, we know that the slope of line u is 3/8. Using the perpendicularity definition, we have


\begin{gathered} (3)/(8)\cdot m_v=-1 \\ m_v=-(8)/(3) \end{gathered}

Therefore, the slope of line v is -8/3.

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