Question

The equation of line u is y=3/8×+6. line v is perpendicular to u. what is the slope of v?

Answer 1

The given equation is

`y=(3)/(8)x+6`

We know that line v is perpendicular to u (the given equation).

The definition for perpendicularity in this case is

`m_u\cdot m_v=-1`

Additionally, from the given equation, we know that the slope of line u is 3/8. Using the perpendicularity definition, we have

`\begin{gathered} (3)/(8)\cdot m_v=-1 \\ m_v=-(8)/(3) \end{gathered}`

Therefore, the slope of line v is -8/3.