A linear function passes through the two points (-1,2) and (2x,8) having slope of 1/2. What is the value of x?
we know that
The slope between two points is equal to
m=(y2-y1)/(x2-x1)
in this problem we have
(x1,y1)=(-1,2)
(x2,y2)=(2x,8)
substitute the given values in the formula
m=(8-2)/(2x+1)
m=6/(2x+1)
rEmember that
m=1/2 ------> given problem
so
1/2=6/(2x+1)
solve for x
multiply in cross
2x+1=12
2x=12-1
2x=11
x=5.5