Question

2Al + 3Cl₂ 2AlCl₃molar mass of AlCl3 => 133 g/molIf you made 10.8 moles of AlCl₃, how many moles of Aluminum would you need?

Answer 1

moles of Al 10.8 moles

Step-by-step explanation

Given:

2Al + 3Cl₂ 2AlCl₃

number of moles of AlCl₃ = 10.8 moles

molar mass of AlCl3 = 133 g/mol

Required: moles of Al

Solution:

Use the stoichiometry to determine the moles of Al

The molar ratio between Al and AlCl3 is 2:2

Therefore the number of moles of Al = 10.8 moles x (2/2) = 10.8 moles