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Write an equation in slope-intercept form for the line described.x-intercept (-7,0), y-intercept (0,1)

User EKrueger
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SOLUTION

The points are


(-7,0)\text{ and (0,1)}

The equation is writing using the formula below


(y-y_1)/(x-x_1)=(y_2-y_1)/(x_(2-)x_1)_{}

where


x_2=0,x_1=-7,y_2=1,y_1=0

Then, we substitute the parameters into the formula above


\begin{gathered} (y-y_1)/(x-x_1)=(y_2-y_1)/(x_(2-)x_1)_{} \\ (y-1)/(x-(-7))=(1-0)/(0-(-7)) \end{gathered}

Simplifying further, we have


\begin{gathered} (y-1)/(x+7)=(1)/(7) \\ 7(y-1)=x+7 \\ 7y-7=x+7 \\ 7y-x-14=0 \\ 7y=x+14 \end{gathered}

Then in the slope-intercept form, we have the equation as


y=(1)/(7)x+2

Therefore the equation of the line in the slope-intercept form is

y=(1/7)x +2

User Aujasvi Chitkara
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