Question

Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end of the first year he had earned $829 in interest. How much was in each account?

Answer 1

Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end of the first year he had earned $829 in interest. How much was in each account?​

Let

x ------> the amount invested in account that paid 9 %

7,600-x ------> the amount invested in account that paid 14%

we have that

9%=9/100=0.09

14%=14/100=0.14

so

(x)*(0.09)+(7,600-x)*(0.14)=829

solve for x

0.09x-0.14x+1,064=829

0.14x-0.09x=1,064-829

0.05x=235

x=4,700

Find the value of (7,600-x)

7,600-4,700=2,900

therefore

the answer is

the amount invested in account that paid 9 % was $4,700

the amount invested in account that paid 14% was $2,900