Andrew invests $7600 in two different accounts. The first account paid 9 %, the second account paid 14% in interest. At the end of the first year he had earned $829 in interest. How much was in each account?
Let
x ------> the amount invested in account that paid 9 %
7,600-x ------> the amount invested in account that paid 14%
we have that
9%=9/100=0.09
14%=14/100=0.14
so
(x)*(0.09)+(7,600-x)*(0.14)=829
solve for x
0.09x-0.14x+1,064=829
0.14x-0.09x=1,064-829
0.05x=235
x=4,700
Find the value of (7,600-x)
7,600-4,700=2,900
therefore
the answer is
the amount invested in account that paid 9 % was $4,700
the amount invested in account that paid 14% was $2,900