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If the area of a triangle is 96 cm, what would be the area of the triangle if the dimensions were tripled?

User Elranu
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1 Answer

1 vote

The area of a triangle is given by


A=(b\cdot h)/(2)

where b is the base and h the height.

If the dimensions are tripled


\begin{gathered} b\longrightarrow3b \\ h\longrightarrow3h \end{gathered}

then, the new area will be


\begin{gathered} A^(\prime)=(3b\cdot3h)/(2) \\ A^(\prime)=(9b\cdot h)/(2) \end{gathered}

which is equal to


\begin{gathered} A^(\prime)=9((b\cdot h)/(2)) \\ \sin ce\text{ the old area A is } \\ \\ A=(b\cdot h)/(2) \\ \text{the new are is} \\ A^(\prime)=9\cdot A \end{gathered}

In other words, the new area A' will be 9 times the old area A. Since A is equal to 96 cm^2, we get


\begin{gathered} A^(\prime)=9\cdot96 \\ A^(\prime)=864 \end{gathered}

that is, the new area will be 864 cm^2.

User Trisha
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