Question

What is the reaction force Ax at point A? Let point E be the origin

Answer 1

`\begin{equation*} 12\text{ }kN \end{equation*}`

Step-by-step explanation

We want to find the reaction force at point A.

To do this, let us take the moment about point E. The sum of the moments about point E must be equal to 0:

`\sum M_E=0`

Therefore, taking the moments of the given forces:

`\begin{gathered} (A_x*1.5)-(3*2)-(3*(2+2))=0 \\ 1.5A_x-6-12=0 \end{gathered}`

Solve the equation for Ax:

`\begin{gathered} 1.5A_x=6+12=18 \\ A_x=(18)/(1.5) \\ A_x=12\text{ }kN \end{gathered}`

That is the answer.