Question

A car, initially at rest, accelerates at 5.70 m/s2 for 6.6 s. How far did it travel in this time?

Answer 1

In order to calculate the displacement during this time, we can use the formula below:

`\Delta S=V_0t+(at^2)/(2)\\`

So, using the initial velocity V0 = 0, acceleration a = 5.7 m/s² and time t = 6.6 s, we have:

`\begin{gathered} \Delta S=0+(5.7\cdot6.6^2)/(2)\\ \\ \Delta S=124.15\text{ m} \end{gathered}`

Therefore the displacement is 124.15 meters.