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Simplify 9c4A. 126B. 15,120C. 5D. 3,024

1 Answer

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The given combination is:


_9C_4

Combinations are given by the following formula:


_nC_r=(n!)/(r!(n-r)!)

Where n is the size of the set and r is the subset size. In this case, n=9 and r=4, let's replace these values and solve:


\begin{gathered} _9C_4=(9!)/(4!(9-4)!) \\ _9C_4=(9!)/(4!*5!) \\ \\ _9C_4=(362880)/(24*120) \\ \\ _9C_4=(362880)/(2880) \\ \\ _9C_4=126 \end{gathered}

The answer is A. 126

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