68.5k views
1 vote
Describe the long run behavior: f(t) = (t-4) (t-2)^3 (t-3)^2 A. infinityB. negative infinityC. zeroD. N/A

User Alonblack
by
7.5k points

1 Answer

7 votes

Given:


f(t)=(t-4)(t-2)^3(t-3)^2

Required:

We need to find the long run behavior.

Step-by-step explanation:

Recall that the long-run behavior of a polynomial function is determined by its leading term.

Consider the given polynomial function.


f(t)=(t-4)(t-2)^3(t-3)^2
f(t)=t(1-(4)/(t))t^3(1-(2)/(t))^3t^2(1-(3)/(t))^2
f(t)=t^6(1-(4)/(t))(1-(2)/(t))^3(1-(3)/(t))^2
\text{ The leading term is }t^6
Let\text{ }g(t)=t^6.

Take the limit as infinity.


\lim_(t\to\infty)g(t)=\lim_(t\to\infty)t^6
g(t)\rightarrow\infty\text{ as t approches }\infty

Take the limit as negative infinity.


\lim_(t\to-\infty)g(t)=\operatorname{\lim}_(t\to-\infty)t^6
g(t)\rightarrow\infty\text{ as t approches -}\infty.

Hence we get


f(t)\rightarrow\infty\text{ as t }\rightarrow\text{ -}\infty\text{ and t}\rightarrow\infty

Final answer:

The long run behavior is infinity.

User Menefee
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories