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How would I find sin B, Cos B, sin C, and Cos C

How would I find sin B, Cos B, sin C, and Cos C-example-1
User Temoncher
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1 Answer

5 votes

The given triangle is

We get hypotenuse =BC=40 by observing the given triangle.

Consider the angle B.

For angle B, the Opposite side is AC=32 adjacent side AB =24.

We know that


\sin \theta=\frac{Opposite\text{ side}}{\text{Hyponetuse}}


\sin B=(AC)/(BC)

Substitute AC=32 and BC=40, we get


\sin B=(32)/(40)=0.8

We know that


\cos \theta=\frac{adjacent\text{ side}}{\text{Hypotenuse}}


\cos B=(AB)/(BC)

Substitute AB=24 and BC=40, we get


\cos B=(24)/(40)=0.6

Consider the angle C.

For angle C, the Opposite side is AB=24 and the adjacent side AC=32.


\sin C=(AB)/(BC)

Substitute AB=24 and BC=40, we get


\sin C=(24)/(40)=0.6


\cos C=(AC)/(BC)

Substitute AC=32 and BC=40, we get


\cos C=(32)/(40)=0.8

Hence the answers are


\sin B=0.8


\cos B=0.6


\sin C=0.6


\cos C=0.8

How would I find sin B, Cos B, sin C, and Cos C-example-1
User Loicgasser
by
8.7k points

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